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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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If in a Δ  ABC,cot⁡A2=b+ca\Delta \;ABC,\cot \frac{A}{2} = \frac{{b + c}}{a}, then the Δ  ABC\Delta \;ABC is
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Correct option: C
Right angled
Option C (Right angled) is correct because given cot⁡A2=b+ca\cot \frac{A}{2} = \frac{{b + c}}{a}, it can be shown that angle B is equal to π2\frac{\pi}{2}.

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