JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

f:\left( { - \infty ,2} \right] \to \left( { - \infty ,4} \right]

be a function defined by

f\left( x \right) = 4x - {x^2}.

Then,

{f^{ - 1}}\left( x \right)

View answer and explanation

Correct option: A

2 - \sqrt {4 - x}

Option B (

\left[ { - 1 - \sqrt 3 \le x \le - 1 + \sqrt 3 } \right]

) is correct because it represents the values of x for which the expression inside the square root is non-negative.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}