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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
If sec⁡  θ=x+14x\sec \,\,\theta = x + \frac{1}{{4x}}, then sec⁡  θ+tan⁡  θ=\sec \,\,\theta + \tan \,\,\theta =

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Correct option: B
2x,  12x2x,\,\,\frac{1}{{2x}}
Option B (2x, 12x2x,\,\frac{1}{{2x}}) is correct because by using the identity sec⁡2θ−tan⁡2θ=1\sec^2 \theta - \tan^2 \theta = 1 and solving the resulting equations, we find that sec⁡θ+tan⁡θ\sec \theta + \tan \theta can be either 2x2x or 12x\frac{1}{{2x}}.

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