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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

If a

\Delta ABC,\;2ca\sin \frac{{A - B + C}}{2}

is equal to

View answer and explanation

Correct option: B

{c^2} + {a^2} - {b^2}

Option B (

{c^2} + {a^2} - {b^2}

) is correct because the expression simplifies to

2ac \cos B

, which equals

{c^2} + {a^2} - {b^2}

by the cosine rule.

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

are altitudes of a

\Delta \;ABC

drawn from the vertices

A,B,C

\Delta

the area of the triangle, then

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

is equal to If the sides of the triangles are

5k,\;6k,\;5k

and radius of incircle is 6, the value of

k

is equal to In a

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

is the area and

2 s

is the sum of the sides of a triangle, then