JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Application +4 | -1

Let

\sum\limits_{k = 1}^{10} {f(a + k) = 16({2^{10}} - 1)}

, where the function

f

satisfies

f(x + y) = f(x)f(y)

for all natural numbers

x

y

and

f(1) = 2

. Then, the natural number

'a'

View answer and explanation

Correct option: C

Option C (3) is correct because after using the given functional equation and solving the resulting exponential equation, the value of a is found to be 3.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

be defined by

f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

equals Let

f: R \rightarrow R

be defined as

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains