JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

f(x)=\left|\begin{array}{ccc}1 & x & (x+1) \\ 2 x & x(x-1) & (x+1) x \\ 3 x(x-1) & x(x-1)(x-2) & x(x-1)(x+1)\end{array}\right|

then

f(50)+f(51)+\ldots \ldots+f(99)

is equal to

View answer and explanation

Correct option: A

Option A (0) is correct because after applying the column operation C3 -> C3 - (C1 + C2), the determinant becomes zero for all x.

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