Equivalent mass of ${\rm{IO}}_4^ - $ when it is converted to ${{\rm{I}}_2}$ in acid medium :

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

Equivalent mass of

\mathrm{IO}_4^ -

when it is converted to

{\mathrm{I}_2}

in acid medium :

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Correct option: B

M/7

Option B (M/7) is correct because the change in oxidation state of iodine is from +7 to 0, resulting in a change of 7, hence the equivalent mass is M/7.

More Questions from REDOX REACTIONS

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The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated

{I_2}

is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction,

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

coefficient of reactants in balanced states are

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }

Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called