The freezing point $(in\;^\circ C)$ of a solution containing $0.1\;g\;of\;{{\rm{K}}_3}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_6}} \right]$ (mol.wt.329) in 100 g of water is : $({K_f} = 1.86\;K\;{\rm{kg}}\;{\rm{mo}}{{\rm{l}}^{ - 1}})$

NEET UG CHEMISTRY MCQ: SOLUTIONS

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The freezing point

(in\;^\circ C)

of a solution containing

0.1\;g\;of\;{\mathrm{K}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]

(mol.wt.329) in 100 g of water is :

({K_f} = 1.86\;K\;\mathrm{kg}\;\mathrm{mo}{\mathrm{l}^{ - 1}})

View answer and explanation

Correct option: A

- 2.3 \times {10^{ - 2}}

Option A (

- 2.3 \times {10^{ - 2}}

) is correct because it is the calculated freezing point depression using the colligative properties formula, van't Hoff factor, and given constants.

Practice All Chapter MCQs →

0.52\,K\,kg\,mo{l^{ - 1}}

A

B

B

A

B

--{0.93^0}C

{K_f}

1.86\mathrm{ }K\mathrm{ }kg\mathrm{ }mo{l^{ - 1}}