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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If ∣z−i∣=1\left| {z - i} \right| = 1 and arg⁡(z)=θ,\arg \left( z \right) = \mathrm{\theta }, where 0<θ<π20 < \mathrm{\theta } < \frac{\pi }{2}, then cot⁡θ−2z\cot \mathrm{\theta } - \frac{2}{z} equals
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Correct option: C
ii
Option C (ii) is correct because after substituting z=r(cos⁡θ+isin⁡θ)z = r(\cos \theta + i\sin \theta ) and simplifying using the given condition ∣z−i∣=1|z - i| = 1, the expression cot⁡θ−2z\cot \mathrm{\theta } - \frac{2}{z} simplifies to ii.

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