JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The domain of the function

f(x)=\exp \left(\sqrt{5 x-3-2 x^2}\right)

View answer and explanation

Correct option: B

[1,3 / 2]

Option B

[1,3 / 2]

is correct because the expression inside the square root must be non-negative, leading to the given interval.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f\left( x \right) = x - \left[ x \right]

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f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}