Typical silt(hard mud) particle of radius $20{\rm{\mu m}}$ is on the top of lake water, its density is $2000{\rm{kg}}{{\rm{m}}^{ - 3}}$ and the viscosity of lake water is 1.0 mPa, density is $1000{\rm{kg}}{{\rm{m}}^{ - 3}}$. If the lake is still(has no internal fluid motion). The terminal speed with which the particle hits the bottom of the lake is ………. ${\rm{mm}}{{\rm{s}}^{ - 1}}$

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1

Typical silt(hard mud) particle of radius

20\mathrm{\mu m}

is on the top of lake water, its density is

2000\mathrm{kg}{\mathrm{m}^{ - 3}}

and the viscosity of lake water is 1.0 mPa, density is

1000\mathrm{kg}{\mathrm{m}^{ - 3}}

. If the lake is still(has no internal fluid motion). The terminal speed with which the particle hits the bottom of the lake is ……….

\mathrm{mm}{\mathrm{s}^{ - 1}}

View answer and explanation

Correct option: C

0.87

Option C (0.87) is correct because it is the terminal speed calculated using Stokes' Law, considering the density difference and viscosity.

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