If $f(x)=\frac{x}{\sqrt{1+x^2}}$, then $(f \circ f \circ)(x)=$

JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f(x)=\frac{x}{\sqrt{1+x^2}}

, then

(f \circ f \circ)(x)=

View answer and explanation

Correct option: B

\frac{x}{\sqrt{1+3 x^2}}

Option B (

\frac{x}{\sqrt{1+3 x^2}}

) is correct because after applying the function three times, the expression simplifies to

\frac{x}{\sqrt{1+3 x^2}}

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