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JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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Analyzing +4 | -1
Among the statements :

(S1) ((p∨q)⇒r)⇔(p⇒r)((p \vee q) \Rightarrow r) \Leftrightarrow(p \Rightarrow r)

(S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))((p \vee q) \Rightarrow r) \Leftrightarrow((p \Rightarrow r) \vee(q \Rightarrow r))
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Correct option: C
neither (S1) nor (S2) is a tautology
Neither (S1) nor (S2) is a tautology because we can find truth values for p, q, and r that make the statements false. A tautology must be true for all possible truth values.

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