The number of $meso$ forms in the following compound is ${\rm{HOOC}}{\rm{.CH}}\left( {{\rm{C}}{{\rm{H}}_3}} \right){\rm{.CH}}\left( {{\rm{OH}}} \right){\rm{.}}$ ${\rm{CH}}\left( {{\rm{Cl}}} \right){\rm{.CH}}\left( {{\rm{OH}}} \right){\rm{CH}}\left( {{\rm{C}}{{\rm{H}}_3}} \right){\rm{.}}$ ${\rm{COOH}}$

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Hard

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Analyzing +4 | -1

The number of

meso

forms in the following compound is

\mathrm{HOOC}\mathrm{.CH}\left( {\mathrm{C}{\mathrm{H}_3}} \right)\mathrm{.CH}\left( {\mathrm{OH}} \right)\mathrm{.}

\mathrm{CH}\left( {\mathrm{Cl}} \right)\mathrm{.CH}\left( {\mathrm{OH}} \right)\mathrm{CH}\left( {\mathrm{C}{\mathrm{H}_3}} \right)\mathrm{.}

\mathrm{COOH}

View answer and explanation

Correct option: B

Option B (4) is correct because the given compound has 4 meso forms due to the presence of multiple chiral centers and a plane of symmetry.