JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

{\left( {\sqrt 5 + \sqrt 3 i} \right)^{33}} = {2^{49}}\;z

, then modulus of the complex number

z

is equal to

View answer and explanation

Correct option: B

\sqrt 2

Option B (

\sqrt{2}

) is correct because the modulus of z is calculated using De Moivre's theorem and properties of complex numbers.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

|\alpha-\beta|

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z \in C

2x = - 1 + \sqrt 3 i

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