Question

The integral $\smallint \frac{{2x\,\, - \,\,3}}{{{{\left( {{x^2} + \,\,x\,\, + 1} \right)}^2}}}\,\,dx$ is equal to

Accepted Answer

$ - \,\,\frac{{8x + 7}}{{{x^2} + x + 1}}\,\, - \,\,\frac{{16}}{{3\,\sqrt 3 }}\,\,{	an ^{ - 1}}\,\,\left( {\frac{{2x + 1}}{3}} ight) + C$

Answer

$ - \,\,\frac{1}{{{x^2} + x + 1}}\,\, - \,\,\frac{4}{3}\,\,{	an ^{ - 1}}\,\,\left( {4x + 3} ight) + C$

Answer

$\frac{1}{{2\left( {{x^2} + x + 1} \right)}}\,\, - \,\,\frac{{{{\left( {2x + 1} \right)}^2}}}{{{{\left( {{x^2} + x + 1} \right)}^2}}} + C$

Answer

$\frac{1}{{4\left( {{x^2} + x + 1} ight)}}\,\, + \,\,\frac{2}{3}\,\,{	an ^{ - 1}}\,\,\left( {2x + 1} ight) + C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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