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JEE PHYSICS MCQ: GRAVITATION

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If

v_o

be the orbital velocity of a satellite in a circular orbit close to the earth's surface and

v_e

is the escape velocity from the earth, then relation between the two is

View answer and explanation

Correct option: C

v_e=\sqrt{2} v_o

Option C (

v_e=\sqrt{2} v_o

) is correct because the escape velocity is

\sqrt{2}

times the orbital velocity near the Earth's surface.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

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. If the body is projected in a direction making an angle of

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with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

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\theta

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