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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
Given SC2H6∘=225 J mol−1 K−1\mathrm{S}_{\mathrm{C}_2 \mathrm{H}_6}^{\circ}=225 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, SC2H4∘=220 J mol−1 K−1, SH2∘=130 J mol−1 K−1.\mathrm{S}_{\mathrm{C}_2 \mathrm{H}_4}^{\circ}=220 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}, \mathrm{~S}_{\mathrm{H}_2}^{\circ}=130 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}. Then ΔS∘\Delta \mathrm{S}^{\circ} for the process C2H4+H2→C2H6\mathrm{C}_2 \mathrm{H}_4+\mathrm{H}_2 \rightarrow \mathrm{C}_2 \mathrm{H}_6 is
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Correct option: B
−125 J-125 \mathrm{~J}
Option B (-125 J) is correct because the change in entropy (ΔS∘\Delta S^{\circ}) is calculated using the formula ΔS∘=Sproducts∘−Sreactants∘\Delta S^{\circ} = S^{\circ}_{products} - S^{\circ}_{reactants}.

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