${\rm{Cu}} + 2{\rm{HCl}} \to {\rm{CuC}}{{\rm{l}}_2} + {{\rm{H}}_2}\left( {\rm{g}} \right)$ $\left[ {E_{C{u^{2 + }}/Cu}^ \circ = + 0.34V} \right]$ ${\rm{Zn}} + 2{\rm{HCl}} \to {\rm{ZnC}}{{\rm{l}}_2} + {{\rm{H}}_2}\left( {\rm{g}} \right)$ $\left[ {E_{Z{n^{2 + }}/Zn}^ \circ = - 0.76V} \right]$ ${\rm{Ag}} + 2{\rm{HCl}} \to {\rm{AgCl}} + \frac{1}{2}{{\rm{H}}_2}\left( {\rm{g}} \right)$ $\left[ {E_{A{g^ + }/Ag}^ \circ = + 0.80V} \right]$ Which of the following reaction is feasible ?

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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\mathrm{Cu} + 2\mathrm{HCl} \to \mathrm{CuC}{\mathrm{l}_2} + {\mathrm{H}_2}\left( \mathrm{g} \right)

\left[ {E_{C{u^{2 + }}/Cu}^ \circ = + 0.34V} \right]

\mathrm{Zn} + 2\mathrm{HCl} \to \mathrm{ZnC}{\mathrm{l}_2} + {\mathrm{H}_2}\left( \mathrm{g} \right)

\left[ {E_{Z{n^{2 + }}/Zn}^ \circ = - 0.76V} \right]

\mathrm{Ag} + 2\mathrm{HCl} \to \mathrm{AgCl} + \frac{1}{2}{\mathrm{H}_2}\left( \mathrm{g} \right)

\left[ {E_{A{g^ + }/Ag}^ \circ = + 0.80V} \right]

Which of the following reaction is feasible ?

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Correct option: A

(ii)

Option A ((ii)) is correct because the reaction with Zinc (Zn) is feasible as it has a negative standard reduction potential, indicating it can be oxidized by HCl.

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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