JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

\Delta \;ABC,\frac{{1 + \cos \left( {A - B} \right)\cos C}}{{1 + \cos \left( {A - C} \right)\cos B}}

is equal to

View answer and explanation

Correct option: D

\frac{{{a^2} + {b^2}}}{{{a^2} + {c^2}}}

Option D (

\frac{{{a^2} + {b^2}}}{{{a^2} + {c^2}}}

) is correct because by using trigonometric identities and the sine rule, the given expression can be simplified to

\frac{{{a^2} + {b^2}}}{{{a^2} + {c^2}}}

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