Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If

f\left( {x + 2y,x - 2y} \right) = xy,

then

f\left( {x,y} \right)

equals

View answer and explanation

Correct option: A

\frac{{{x^2} - {y^2}}}{8}

Option A (

\frac{{{{x^2} - {y^2}}}}{{8}}

) is correct because it is the result of substituting

x

and

y

in terms of

u

and

v

into the given function.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}