What is the ox. no. of Mn in ${{\rm{K}}_2}{\rm{Mn}}{{\rm{O}}_4}?$

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Easy

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Application +4 | -1

What is the ox. no. of Mn in

{\mathrm{K}_2}\mathrm{Mn}{\mathrm{O}_4}?

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Correct option: C

+ 2

Option B (+6) is correct because the oxidation number of Mn in K2MnO4 is calculated by considering the oxidation states of K and O.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }