NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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Analyzing +4 | -1

Tests on an aqueous solution of sodium salt having an anion

\mathrm{X}^{\mathrm{n}-}

gives the following results.

Anion

\mathrm{X}^{\mathrm{n}-} \stackrel{\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7}{\longrightarrow}

Green solution

Anion

\mathrm{X}^{\mathrm{n}-} \stackrel{\mathrm{Pb}(\mathrm{OAc})_2}{\longrightarrow}

Black precipitate

Which of the following could be

\mathrm{X}^{\mathrm{n}-}

View answer and explanation

Correct option: C

\mathrm{S}^{2-}

Option C (

\mathrm{S}^{2-}

) is correct because sulfide ions react with dichromate to form a green solution and with lead acetate to form a black precipitate.

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