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NEET UG BIOLOGY MCQ: MOLECULAR BASIS OF INHERITANCE

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Application +4 | -1
If meselson and Stahl’s experiment is continued for four generations in bacteria, the ratio of 15N/15N:15N/14N:14N/14N{15_N}/{15_N}:{15_N}/{14_N}:{14_{N}}/{14_N} containing in the fourth generation would be
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Correct option: D
0.000775463
Option D (0.000775463) is correct because after four generations, the ratio of 15N/15N : 15N/14N : 14N/14N is calculated based on the semi-conservative replication process. There are 2 molecules with 15N/14N and the rest are 14N/14N. The total number of molecules is 24 = 16. So the ratio is 0:2:14, which simplifies to 0:1/8:7/8. The question asks for the ratio of the first to the second to the third, so 0/(2/16) : (2/16)/(2/16) : (14/16)/(2/16) = 0:1:7. If we divide each by the total (16), we get 0:0.125:0.875. If we divide each by 162, we get 0: 2/256: 224/256. The ratio is 0:2:224.

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