1 mole of '$\mathrm{A}$', 1.5 mole of '$\mathrm{B}$' and 2 mole of '$\mathrm{C}$' are taken in a vessel of volume one litre. At equilibrium concentration of $\mathrm{C}$ is $0.5 \mathrm{~mole} / \mathrm{L}$. Equilibrium constant for the reaction $\mathrm{A}{(\mathrm{g})}+\mathrm{B}{(\mathrm{g})} \rightleftharpoons \mathrm{C}{(\mathrm{g})}$ is

NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

1 of 1

Application +4 | -1

1 mole of '

\mathrm{A}

', 1.5 mole of '

\mathrm{B}

' and 2 mole of '

\mathrm{C}

' are taken in a vessel of volume one litre. At equilibrium concentration of

\mathrm{C}

0.5 \mathrm{~mole} / \mathrm{L}

. Equilibrium constant for the reaction

\mathrm{A}{(\mathrm{g})}+\mathrm{B}{(\mathrm{g})} \rightleftharpoons \mathrm{C}{(\mathrm{g})}

View answer and explanation

Correct option: B

0.066

Option B (0.066) is correct because it represents the equilibrium constant calculated based on the given changes in concentration.

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}