JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In triangle

\mathrm{ABC}

given

9 a^2+9 b^2-17 c^2=0

.If

\frac{\cot \mathrm{A}+\cot \mathrm{B}}{\cot \mathrm{C}}=\frac{m}{n}

, then the value of

(m+n)

equals

View answer and explanation

Correct option: A

Option A (13) is correct because by using the Law of Cosines and trigonometric identities, the given equation simplifies to (cot A + cot B) / cot C = 9/4, and thus m+n = 13.

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{p_1},{p_2},{p_3}

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\Delta \;ABC

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\Delta

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5k,\;6k,\;5k

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, if

a = \left( {b - c} \right)\sec \theta

, then

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, where

\Delta

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\Delta \;ABC

, then

\tan A

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A

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2 s

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