JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A star of mass twice the solar mass and radius

10^6 \mathrm{~km}

rotates about its axis with an angular speed of

10^{-6} \mathrm{~rad} \mathrm{~s}^{-1}

. What is the angular speed of the star when it collapses (due to inward gravitational force) to a radius of

10^4 \mathrm{~km}

? Solar mass

1.99 \times 10^{30} \mathrm{~kg}

View answer and explanation

Correct option: A

0.01 \mathrm{~rad} \mathrm{~s}^{-1}

Option A (

0.01 \mathrm{~rad} \mathrm{~s}^{-1}

) is correct because angular momentum is conserved during the collapse, and the angular speed is inversely proportional to the square of the radius.

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)