Question

If $x = h + a\,\,\sec \,\,	heta $ and $y = k + b\,{m{cosec}}\;\,	heta $. Then,

Accepted Answer

$\frac{{{a^2}}}{{{{\left( {x - h} \right)}^2}}}\,\, + \,\,\frac{{{b^2}}}{{{{\left( {y - k} \right)}^2}}} = 1$

Answer

$\frac{{{a^2}}}{{{{\left( {x + h} \right)}^2}}}\,\, - \,\,\frac{{{b^2}}}{{{{\left( {y + k} \right)}^2}}} = 1$

Answer

$\frac{{{{\left( {x - h} \right)}^2}}}{{{a^2}}}\,\, + \,\,\frac{{{{\left( {y - k} \right)}^2}}}{{{b^2}}} = 1$

Answer

$\frac{{{{\left( {x - h} \right)}^2}}}{{{a^2}\;}}\,\, - \,\,\frac{{{{\left( {y - k} \right)}^2}}}{{{b^2}}} = 1$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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