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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
The value of lim⁡x→0(cos⁡ax)cosec⁡2bx\lim \limits_{{x \rightarrow 0}}(\cos a x)^{\operatorname{cosec}^2 b x} is
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Correct option: C
e(−a22b2)e^{\left(-\frac{a^2}{2 b^2}\right)}
Option C (e(−a22b2)e^{\left(-\frac{a^2}{2 b^2}\right)}) is correct because it represents the limit of the given expression as x approaches 0, evaluated using exponential and trigonometric limit properties.

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