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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫x1+x4dx=\int \frac{x}{1+x^4} d x=
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Correct option: B
12tan⁡−1x2+c\frac{1}{2} \tan ^{-1} x^2+c
Option B is correct because substituting t=x2t = x^2 transforms the integral to 12∫11+t2dt\frac{1}{2} \int \frac{1}{1 + t^2} dt, which equals 12tan⁡−1t+c=12tan⁡−1x2+c\frac{1}{2} \tan^{-1} t + c = \frac{1}{2} \tan^{-1} x^2 + c.

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