If $\frac{d y}{d x}=\cos (x+y), y\left(\frac{\pi}{2}\right)=0$, then $y(0)=$

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1

\frac{d y}{d x}=\cos (x+y), y\left(\frac{\pi}{2}\right)=0

, then

y(0)=

View answer and explanation

Correct option: D

-2 \tan ^{-1}\left(\frac{\pi}{2}-1\right)

Option D (

-2 \tan ^{-1}\left(\frac{\pi}{2}-1\right)

) is correct because it is the solution obtained after solving the given differential equation with the initial condition.

Practice All Chapter MCQs →

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y=y(t)

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\alpha>0, \beta>0

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\lim \limits_{{x \rightarrow \infty}} y(t)