JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

Let

a, b

and

c

be the sides of a triangle and

\frac{a^2+b^2+c^2}{a b+b c+c a}=P

. Then

View answer and explanation

Correct option: D

1 \leq P < 2

Option D (

1 \leq P < 2

) is correct because the ratio

\frac{a^2+b^2+c^2}{ab+bc+ca}

is always greater than or equal to 1, and less than 2 for a triangle.

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