If an object starts from rest and covers angle of $60 \mathrm{~rad}$ in $10 \mathrm{~s}$ in circular motion, then magnitude of its angular acceleration will be

$1.5 \mathrm{~rad} \mathrm{~s}^{-2}$

$2.5 \mathrm{~rad} \mathrm{~s}^{-2}$

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

If an object starts from rest and covers angle of

60 \mathrm{~rad}

10 \mathrm{~s}

in circular motion, then magnitude of its angular acceleration will be

View answer and explanation

Correct option: A

1.2 \mathrm{~rad} \mathrm{~s}^{-2}

Option A (1.2 rad s⁻²) is correct because it correctly applies the rotational motion equation to find the angular acceleration.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)