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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
If xcos⁡θ=ycos⁡(θ+2π3)=zcos⁡(θ−2π3)\frac{x}{\cos \theta}=\frac{y}{\cos \left(\theta+\frac{2 \pi}{3}\right)}=\frac{z}{\cos \left(\theta-\frac{2 \pi}{3}\right)}, then x+y+zx+y+z is equal to
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Correct option: C
0
Option C (0) is correct because using the given condition and the cosine addition formula, the expression simplifies to zero.

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