JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

The equation

\bar z = \bar a + \frac{{{r^2}}}{{\left( {z - a} \right)}},\;\,r > 0

represents

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Correct option: C

A circle

Option C (A circle) is correct because the given equation can be rearranged into the general form of a circle equation in the complex plane.

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{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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