If $15 \sin ^4 x+10 \cos ^4 x=6$, Then $\tan ^2 x=$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

15 \sin ^4 x+10 \cos ^4 x=6

, Then

\tan ^2 x=

View answer and explanation

Correct option: C

2 / 3

Option C (

2 / 3

) is correct because by using the identity

\sin^2 x + \cos^2 x = 1

and simplifying the given equation, we can find that

\tan^2 x = 2/3

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\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=