JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

0 < x < \pi

, and

\sin x+\cos x=1 / 3

, then a possible value of

\tan x

View answer and explanation

Correct option: A

\frac{1}{8}(-9+\sqrt{17})

The correct answer is A (

\frac{1}{8}(-9+\sqrt{17})

) because by squaring the given equation and using trigonometric identities, we can solve for tan x.

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C

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