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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
Out of the following functions representing motion of a particle which represents SHM (i) y=sin⁡ωt−cos⁡ωty = \sin \omega t - \cos \omega t (ii) y=sin⁡3ωty = {\sin ^3}\omega t (iii) y=5cos⁡(3π4−3ωt)y = 5\cos \left( {\frac{{3\pi }}{4} - 3\omega t} \right) (iv) y=1+ωt+ω2t2y = 1 + \omega t + {\omega ^2}{t^2}
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Correct option: D
Only (i) and (iii)
Option D (Only (i) and (iii)) is correct because only these functions can be expressed in the form Asin⁡(ωt+ϕ)A\sin(\omega t + \phi) or Acos⁡(ωt+ϕ)A\cos(\omega t + \phi).

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