JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

\Delta \;ABC,\;{\left( {a - b} \right)^2}{\cos ^2}\frac{C}{2} + {\left( {a + b} \right)^2}{\sin ^2}\frac{C}{2}

is equal to

View answer and explanation

Correct option: C

{c^2}

Option C (

{c^2}

) is correct because the expression simplifies to

c^2

using trigonometric identities and the cosine rule.

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