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NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Analyzing +4 | -1
E∘E^\circ values of some redox couples are given below on the basis of these values. Choose the correct option
E∘E^\circ values:
Br2/Br−=+1.90Ag+/Ag(s)=+0.80Cu2+/Cu(s)=+0.34I2(s)/I−=+0.54\begin{array}{l} B{r_2}\mathrm{/}B{r^ - } = + 1.90\\ A{g^ + }\mathrm{/}Ag(s) = + 0.80\\ C{u^{2 + }}\mathrm{/}Cu(s) = + 0.34\\ {I_2}(s)\mathrm{/}{I^ - } = + 0.54 \end{array}
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Correct option: D
CuCu will reduce Br2B{r_2}
Option D (CuCu will reduce Br2B{r_2}) is correct because copper has a lower reduction potential than bromine, meaning it can be oxidized (act as a reducing agent) to reduce bromine.

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