JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

x_r=\cos \frac{\pi}{2^r}+i \sin \frac{\pi}{2^r}

, then the value of

x_1 \times x_2 \times x_3 \times \ldots \times \infty

View answer and explanation

Correct option: D

-1

Option D (-1) is correct because the product of the complex numbers simplifies to cos(π) + i sin(π), which equals -1.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

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