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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A wheel is rotating at 480 rpm480 \mathrm{~rpm}. Find the magnitude of angular acceleration required to stop the wheel in 8 seconds?
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Correct option: A
2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}
Option A (2π rad.s−22 \pi\mathrm{~rad}.\mathrm{s}^{-2}) is correct because it is the angular acceleration required to stop the wheel, calculated using the formula α=ΔωΔt\alpha = \frac{\Delta \omega}{\Delta t}.

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