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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
The domain of the function f(x)=sin⁡−1{log⁡2(12x2)}f(x)=\sin ^{-1}\left\{\log _2\left(\frac{1}{2} x^2\right)\right\} is
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Correct option: C
[−2,−1]∪[1,2][-2,-1] \cup[1,2]
Option C ([-2,-1]∪\cup[1,2]) is correct because it represents the domain for which the function is defined, considering the logarithmic and inverse sine functions.

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