The terminal speed of a sphere of gold $\left( {{\rm{density}} = 19.5{\rm{kg}}{{\rm{m}}^{ - 3}}} \right)$ is $0.2{\rm{m}}{{\rm{s}}^{ - 1}}$ in a viscous liquid $\left( {{\rm{density}} = 1.5{\rm{kg}}{{\rm{m}}^{ - 3}}} \right)$. Then the terminal speed of a sphere of silver $\left( {{\rm{density}} = 10.5{\rm{kg}}{{\rm{m}}^{ - 3}}} \right)$ of the same size in the same liquid is

$1.133{\rm{m}}{{\rm{s}}^{ - 1}}$

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

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Application +4 | -1

The terminal speed of a sphere of gold

\left( {\mathrm{density} = 19.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right)

0.2\mathrm{m}{\mathrm{s}^{ - 1}}

in a viscous liquid

\left( {\mathrm{density} = 1.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right)

. Then the terminal speed of a sphere of silver

\left( {\mathrm{density} = 10.5\mathrm{kg}{\mathrm{m}^{ - 3}}} \right)

of the same size in the same liquid is

View answer and explanation

Correct option: A

0.1\mathrm{m}{\mathrm{s}^{ - 1}}

Option A (

0.1\mathrm{m}{\mathrm{s}^{ - 1}}

) is correct because the terminal velocity is proportional to the difference in densities between the sphere and the liquid.