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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
If f(x)=x−1x+1f(x)=\frac{x-1}{x+1}, then f(f(ax))f(f(a x)) is equal to
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Correct option: C
f(x)−1a(f(x)+1)\frac{f(x)-1}{a(f(x)+1)}
The correct answer is C (f(x)−1a(f(x)+1)\frac{{f(x)-1}}{{a(f(x)+1)}}) because it is the result of correctly substituting f(x)f(x) into the composite function f(f(ax))f(f(ax)).

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