JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

Let

a

be a positive real number and

f: \mathbb{R} \rightarrow \mathbb{R}

a function such that

f(x+a)=1+\sqrt{2 f(x)-f^2(x)} \text { for all } x \in \mathbb{R}

then a period of

f

View answer and explanation

Correct option: A

2 a

The correct answer is A (

2a

) because the function

f

has a period of

2a

, derived by substituting

x+a

into the given equation and simplifying.

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