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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
A cylinder of gas is assumed to contain 11.2 kg of butane (C4H10)\mathrm{(}{\mathrm{C}_4}{\mathrm{H}_{10}}). If a normal family needs 20000 kJ of energy per day. The cylinder will last (Given that ∆H for combustion of butane is -2658 kJ)
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Correct option: C
26 days
Option C (26 days) is correct. It is calculated by determining the total energy available from the butane and dividing it by the daily energy requirement.

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