Skip to main content
Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
1 of 1
Application +4 | -1
The domain of the function f(x)=sin⁡−1{(1+ex)−1}f(x)=\sin ^{-1}\left\{\left(1+e^{x}\right)^{-1}\right\} is
View answer and explanation
Correct option: A
(14,13)\left(\frac{1}{4}, \frac{1}{3}\right)
The provided answer and solution steps are incorrect. The correct answer is (-∞, ∞). The range of arcsin is [-π/2, π/2] and the argument of arcsin must be between -1 and 1. Since e^x is always positive, 1/(1+e^x) is always between 0 and 1. Therefore, the domain is all real numbers.

More Questions from FUNCTIONS

Practice All Chapter MCQs →
If f:(−∞,2]⟶(−∞,4]f:(-\infty, 2] \longrightarrow(-\infty, 4], where f(x)=x(4−x)f(x)=x(4-x), then f−1(x)f^{-1}(x) is given by: If g(f(x))=∣sin⁡x∣g(f(x))=|\sin x| and f(g(x))=(sin⁡x)2f(g(x))=(\sin \sqrt{x})^2, then Let f:(2,  3)→(0,  1)f:\left( {2,\;3} \right) \to \left( {0,\;1} \right) be defined by f(x)=x−[x]f\left( x \right) = x - \left[ x \right], then f−1(x){f^{ - 1}}\left( x \right) equals Let f:R→Rf: R \rightarrow R be defined as f(x)=x4f(x)=x^4, Choose the correct answer. Which of the following functions are odd functions Let f(x)=(x+1)2−1(x≥−1)f(x)=(x+1)^2-1(x \geq-1). Then the set S={x:f(x)=f−1(x)}S=\left\{x: f(x)=f^{-1}(x)\right\} contains
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →