NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Application +4 | -1

The hydrogen electrode is dipped in a solution of

\mathrm{pH} = 3{\kern 1pt} {\kern 1pt} {\kern 1pt} \mathrm{at}{\kern 1pt} {\kern 1pt} {\kern 1pt} {25^ \circ }C

. The potential of the cell would be (

\mathrm{the value of}\frac{{2.303RT}}{T}\mathrm{is}{\kern 1pt} {\kern 1pt} {\kern 1pt} 0.059\mathrm{V}

)

View answer and explanation

Correct option: C

-0.177 V

Option C (-0.177 V) is correct because it is the calculated potential of the hydrogen electrode using the Nernst equation with the given pH.

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