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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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A photon and electron have same de-Broglie wavelength. Give that vv is the speed of electron and cc is the velocity of light. Ee,  Ep{E_e},\;{E_p} are the kinetic energy of electron and photon respectively. pe,  ph{p_e},\;{p_h} are the momentum of electron and photon respectively. Then which of the following relation is correct?
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Correct option: A
EeEp=v2c\frac{{{E_e}}}{{{E_p}}} = \frac{v}{{2c}}
Option A is correct because the ratio of kinetic energy of electron to photon is v/2c, derived from their de-Broglie wavelengths and energy equations.

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